One way to be sigil-less
作者:gugod 發佈於:It is possible to write such sigil-less perl program:
foo = 42;
say foo;
The trick is to declare foo
as a lvalue sub:
my $foo;
sub foo :lvalue { $foo }
Since $foo
is a scalar, it works for hashref and arrayref too:
foo = { ans => 42 };
say foo->{ans}
# => 42
foo = [42, 43, 44]
say foo->[0]
# => 42
This appears to me an interesting smell of a new PerlX module.